Card_Do_Pwd.asp
资源名称:eat.rar [点击查看]
上传用户:jisenq
上传日期:2014-06-29
资源大小:7216k
文件大小:1k
源码类别:
数据库编程
开发平台:
ASP/ASPX
- <%
- Function Encrypt(theNumber)
- ''加密后
- On Error Resume Next
- Dim n, szEnc, t, HiN, LoN, i
- n = CDbl((theNumber + 1570) ^ 2 - 7 * (theNumber + 1570) - 450)
- If n < 0 Then szEnc = "R" Else szEnc = "J"
- n = CStr(abs(n))
- For i = 1 To Len(n) step 2
- t = Mid(n, i, 2)
- If Len(t) = 1 Then
- szEnc = szEnc & t
- Exit For
- End If
- HiN = (CInt(t) And 240) / 16
- LoN = CInt(t) And 15
- szEnc = szEnc & Chr(Asc("M") + HiN) & Chr(Asc("C") + LoN)
- Next
- Encrypt = szEnc
- End Function
- Function Decrypt(theNumber)
- ''解密后
- On Error Resume Next
- Dim e, n, sign, t, HiN, LoN, NewN, i
- e = theNumber
- If Left(e, 1) = "R" Then sign = -1 Else sign = 1
- e = Mid(e, 2)
- NewN = ""
- For i = 1 To Len(e) step 2
- t = Mid(e, i, 2)
- If Asc(t) >= Asc("0") And Asc(t) <= Asc("9") Then
- NewN = NewN & t
- Exit For
- End If
- HiN = Mid(t, 1, 1)
- LoN = Mid(t, 2, 1)
- HiN = (Asc(HiN) - Asc("M")) * 16
- LoN = Asc(LoN) - Asc("C")
- t = CStr(HiN Or LoN)
- If Len(t) = 1 Then t = "0" & t
- NewN = NewN & t
- Next
- e = CDbl(NewN) * sign
- Decrypt = CLng((7 + sqr(49 - 4 * (-450 - e))) / 2 - 1570)
- End Function
- 'Dim Need_Do_Pwd_Str
- 'Need_Do_Str = "123456"
- 'response.Write("加密后:"&Encrypt(Need_Do_Pwd_Str))
- 'response.Write("<br>解密后:"&Decrypt( Encrypt(Need_Do_Pwd_Str) ))
- %>