10_googleimage.lua
资源名称:vlc-1.0.5.zip [点击查看]
上传用户:kjfoods
上传日期:2020-07-06
资源大小:29949k
文件大小:2k
源码类别:
midi
开发平台:
Unix_Linux
- --[[
- Gets an artwork from images.google.com
- $Id$
- Copyright © 2007 the VideoLAN team
- This program is free software; you can redistribute it and/or modify
- it under the terms of the GNU General Public License as published by
- the Free Software Foundation; either version 2 of the License, or
- (at your option) any later version.
- This program is distributed in the hope that it will be useful,
- but WITHOUT ANY WARRANTY; without even the implied warranty of
- MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
- GNU General Public License for more details.
- You should have received a copy of the GNU General Public License
- along with this program; if not, write to the Free Software
- Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston MA 02110-1301, USA.
- --]]
- -- Replace non alphanumeric char by +
- function get_query( title )
- -- If we have a .EXT remove the extension.
- str = string.gsub( title, "(.*)%....$", "%1" )
- return string.gsub( str, "([^%w ])",
- function (c) return string.format ("%%%02X", string.byte(c)) end)
- end
- -- Return the artwork
- function fetch_art()
- if vlc.artist and vlc.album then
- title = vlc.artist.." "..vlc.album
- elseif vlc.title and vlc.artist then
- title = vlc.artist.." "..vlc.title
- elseif vlc.title then
- title = vlc.title
- elseif vlc.name then
- title = vlc.name
- else
- return nil
- end
- fd = vlc.stream( "http://images.google.com/images?q=" .. get_query( title ) )
- page = fd:read( 65653 )
- fd = nil
- _, _, arturl = string.find( page, "imgurl=([^&]+)" )
- return arturl
- end