crypt-bsd-4.3-reno.c
资源名称:des.zip [点击查看]
上传用户:zhh515
上传日期:2007-01-06
资源大小:966k
文件大小:8k
源码类别:
加密解密
开发平台:
C/C++
- #if defined(LIBC_SCCS) && !defined(lint)
- static char sccsid[] = "@(#)crypt.c 5.3 (Berkeley) 5/11/90";
- #endif LIBC_SCCS and not lint
- /*
- * This program implements the
- * Proposed Federal Information Processing
- * Data Encryption Standard.
- * See Federal Register, March 17, 1975 (40FR12134)
- */
- /*
- * Initial permutation,
- */
- static char IP[] = {
- 58,50,42,34,26,18,10, 2,
- 60,52,44,36,28,20,12, 4,
- 62,54,46,38,30,22,14, 6,
- 64,56,48,40,32,24,16, 8,
- 57,49,41,33,25,17, 9, 1,
- 59,51,43,35,27,19,11, 3,
- 61,53,45,37,29,21,13, 5,
- 63,55,47,39,31,23,15, 7,
- };
- /*
- * Final permutation, FP = IP^(-1)
- */
- static char FP[] = {
- 40, 8,48,16,56,24,64,32,
- 39, 7,47,15,55,23,63,31,
- 38, 6,46,14,54,22,62,30,
- 37, 5,45,13,53,21,61,29,
- 36, 4,44,12,52,20,60,28,
- 35, 3,43,11,51,19,59,27,
- 34, 2,42,10,50,18,58,26,
- 33, 1,41, 9,49,17,57,25,
- };
- /*
- * Permuted-choice 1 from the key bits
- * to yield C and D.
- * Note that bits 8,16... are left out:
- * They are intended for a parity check.
- */
- static char PC1_C[] = {
- 57,49,41,33,25,17, 9,
- 1,58,50,42,34,26,18,
- 10, 2,59,51,43,35,27,
- 19,11, 3,60,52,44,36,
- };
- static char PC1_D[] = {
- 63,55,47,39,31,23,15,
- 7,62,54,46,38,30,22,
- 14, 6,61,53,45,37,29,
- 21,13, 5,28,20,12, 4,
- };
- /*
- * Sequence of shifts used for the key schedule.
- */
- static char shifts[] = {
- 1,1,2,2,2,2,2,2,1,2,2,2,2,2,2,1,
- };
- /*
- * Permuted-choice 2, to pick out the bits from
- * the CD array that generate the key schedule.
- */
- static char PC2_C[] = {
- 14,17,11,24, 1, 5,
- 3,28,15, 6,21,10,
- 23,19,12, 4,26, 8,
- 16, 7,27,20,13, 2,
- };
- static char PC2_D[] = {
- 41,52,31,37,47,55,
- 30,40,51,45,33,48,
- 44,49,39,56,34,53,
- 46,42,50,36,29,32,
- };
- /*
- * The C and D arrays used to calculate the key schedule.
- */
- static char C[28];
- static char D[28];
- /*
- * The key schedule.
- * Generated from the key.
- */
- static char KS[16][48];
- /*
- * The E bit-selection table.
- */
- static char E[48];
- static char e[] = {
- 32, 1, 2, 3, 4, 5,
- 4, 5, 6, 7, 8, 9,
- 8, 9,10,11,12,13,
- 12,13,14,15,16,17,
- 16,17,18,19,20,21,
- 20,21,22,23,24,25,
- 24,25,26,27,28,29,
- 28,29,30,31,32, 1,
- };
- /*
- * Set up the key schedule from the key.
- */
- setkey(key)
- char *key;
- {
- register i, j, k;
- int t;
- /*
- * First, generate C and D by permuting
- * the key. The low order bit of each
- * 8-bit char is not used, so C and D are only 28
- * bits apiece.
- */
- for (i=0; i<28; i++) {
- C[i] = key[PC1_C[i]-1];
- D[i] = key[PC1_D[i]-1];
- }
- /*
- * To generate Ki, rotate C and D according
- * to schedule and pick up a permutation
- * using PC2.
- */
- for (i=0; i<16; i++) {
- /*
- * rotate.
- */
- for (k=0; k<shifts[i]; k++) {
- t = C[0];
- for (j=0; j<28-1; j++)
- C[j] = C[j+1];
- C[27] = t;
- t = D[0];
- for (j=0; j<28-1; j++)
- D[j] = D[j+1];
- D[27] = t;
- }
- /*
- * get Ki. Note C and D are concatenated.
- */
- for (j=0; j<24; j++) {
- KS[i][j] = C[PC2_C[j]-1];
- KS[i][j+24] = D[PC2_D[j]-28-1];
- }
- }
- for(i=0;i<48;i++)
- E[i] = e[i];
- }
- /*
- * The 8 selection functions.
- * For some reason, they give a 0-origin
- * index, unlike everything else.
- */
- static char S[8][64] = {
- 14, 4,13, 1, 2,15,11, 8, 3,10, 6,12, 5, 9, 0, 7,
- 0,15, 7, 4,14, 2,13, 1,10, 6,12,11, 9, 5, 3, 8,
- 4, 1,14, 8,13, 6, 2,11,15,12, 9, 7, 3,10, 5, 0,
- 15,12, 8, 2, 4, 9, 1, 7, 5,11, 3,14,10, 0, 6,13,
- 15, 1, 8,14, 6,11, 3, 4, 9, 7, 2,13,12, 0, 5,10,
- 3,13, 4, 7,15, 2, 8,14,12, 0, 1,10, 6, 9,11, 5,
- 0,14, 7,11,10, 4,13, 1, 5, 8,12, 6, 9, 3, 2,15,
- 13, 8,10, 1, 3,15, 4, 2,11, 6, 7,12, 0, 5,14, 9,
- 10, 0, 9,14, 6, 3,15, 5, 1,13,12, 7,11, 4, 2, 8,
- 13, 7, 0, 9, 3, 4, 6,10, 2, 8, 5,14,12,11,15, 1,
- 13, 6, 4, 9, 8,15, 3, 0,11, 1, 2,12, 5,10,14, 7,
- 1,10,13, 0, 6, 9, 8, 7, 4,15,14, 3,11, 5, 2,12,
- 7,13,14, 3, 0, 6, 9,10, 1, 2, 8, 5,11,12, 4,15,
- 13, 8,11, 5, 6,15, 0, 3, 4, 7, 2,12, 1,10,14, 9,
- 10, 6, 9, 0,12,11, 7,13,15, 1, 3,14, 5, 2, 8, 4,
- 3,15, 0, 6,10, 1,13, 8, 9, 4, 5,11,12, 7, 2,14,
- 2,12, 4, 1, 7,10,11, 6, 8, 5, 3,15,13, 0,14, 9,
- 14,11, 2,12, 4, 7,13, 1, 5, 0,15,10, 3, 9, 8, 6,
- 4, 2, 1,11,10,13, 7, 8,15, 9,12, 5, 6, 3, 0,14,
- 11, 8,12, 7, 1,14, 2,13, 6,15, 0, 9,10, 4, 5, 3,
- 12, 1,10,15, 9, 2, 6, 8, 0,13, 3, 4,14, 7, 5,11,
- 10,15, 4, 2, 7,12, 9, 5, 6, 1,13,14, 0,11, 3, 8,
- 9,14,15, 5, 2, 8,12, 3, 7, 0, 4,10, 1,13,11, 6,
- 4, 3, 2,12, 9, 5,15,10,11,14, 1, 7, 6, 0, 8,13,
- 4,11, 2,14,15, 0, 8,13, 3,12, 9, 7, 5,10, 6, 1,
- 13, 0,11, 7, 4, 9, 1,10,14, 3, 5,12, 2,15, 8, 6,
- 1, 4,11,13,12, 3, 7,14,10,15, 6, 8, 0, 5, 9, 2,
- 6,11,13, 8, 1, 4,10, 7, 9, 5, 0,15,14, 2, 3,12,
- 13, 2, 8, 4, 6,15,11, 1,10, 9, 3,14, 5, 0,12, 7,
- 1,15,13, 8,10, 3, 7, 4,12, 5, 6,11, 0,14, 9, 2,
- 7,11, 4, 1, 9,12,14, 2, 0, 6,10,13,15, 3, 5, 8,
- 2, 1,14, 7, 4,10, 8,13,15,12, 9, 0, 3, 5, 6,11,
- };
- /*
- * P is a permutation on the selected combination
- * of the current L and key.
- */
- static char P[] = {
- 16, 7,20,21,
- 29,12,28,17,
- 1,15,23,26,
- 5,18,31,10,
- 2, 8,24,14,
- 32,27, 3, 9,
- 19,13,30, 6,
- 22,11, 4,25,
- };
- /*
- * The current block, divided into 2 halves.
- */
- static char L[64], *R = L+32;
- static char tempL[32];
- static char f[32];
- /*
- * The combination of the key and the input, before selection.
- */
- static char preS[48];
- /*
- * The payoff: encrypt a block.
- */
- encrypt(block, edflag)
- char *block;
- {
- int i, ii;
- register t, j, k;
- /*
- * First, permute the bits in the input
- */
- for (j=0; j<64; j++)
- L[j] = block[IP[j]-1];
- /*
- * Perform an encryption operation 16 times.
- */
- for (ii=0; ii<16; ii++) {
- /*
- * Set direction
- */
- if (edflag)
- i = 15-ii;
- else
- i = ii;
- /*
- * Save the R array,
- * which will be the new L.
- */
- for (j=0; j<32; j++)
- tempL[j] = R[j];
- /*
- * Expand R to 48 bits using the E selector;
- * exclusive-or with the current key bits.
- */
- for (j=0; j<48; j++)
- preS[j] = R[E[j]-1] ^ KS[i][j];
- /*
- * The pre-select bits are now considered
- * in 8 groups of 6 bits each.
- * The 8 selection functions map these
- * 6-bit quantities into 4-bit quantities
- * and the results permuted
- * to make an f(R, K).
- * The indexing into the selection functions
- * is peculiar; it could be simplified by
- * rewriting the tables.
- */
- for (j=0; j<8; j++) {
- t = 6*j;
- k = S[j][(preS[t+0]<<5)+
- (preS[t+1]<<3)+
- (preS[t+2]<<2)+
- (preS[t+3]<<1)+
- (preS[t+4]<<0)+
- (preS[t+5]<<4)];
- t = 4*j;
- f[t+0] = (k>>3)&01;
- f[t+1] = (k>>2)&01;
- f[t+2] = (k>>1)&01;
- f[t+3] = (k>>0)&01;
- }
- /*
- * The new R is L ^ f(R, K).
- * The f here has to be permuted first, though.
- */
- for (j=0; j<32; j++)
- R[j] = L[j] ^ f[P[j]-1];
- /*
- * Finally, the new L (the original R)
- * is copied back.
- */
- for (j=0; j<32; j++)
- L[j] = tempL[j];
- }
- /*
- * The output L and R are reversed.
- */
- for (j=0; j<32; j++) {
- t = L[j];
- L[j] = R[j];
- R[j] = t;
- }
- /*
- * The final output
- * gets the inverse permutation of the very original.
- */
- for (j=0; j<64; j++)
- block[j] = L[FP[j]-1];
- }
- char *
- crypt(pw,salt)
- char *pw;
- char *salt;
- {
- register i, j, c;
- int temp;
- static char block[66], iobuf[16];
- for(i=0; i<66; i++)
- block[i] = 0;
- for(i=0; (c= *pw) && i<64; pw++){
- for(j=0; j<7; j++, i++)
- block[i] = (c>>(6-j)) & 01;
- i++;
- }
- setkey(block);
- for(i=0; i<66; i++)
- block[i] = 0;
- for(i=0;i<2;i++){
- c = *salt++;
- iobuf[i] = c;
- if(c>'Z') c -= 6;
- if(c>'9') c -= 7;
- c -= '.';
- for(j=0;j<6;j++){
- if((c>>j) & 01){
- temp = E[6*i+j];
- E[6*i+j] = E[6*i+j+24];
- E[6*i+j+24] = temp;
- }
- }
- }
- for(i=0; i<25; i++)
- encrypt(block,0);
- for(i=0; i<11; i++){
- c = 0;
- for(j=0; j<6; j++){
- c <<= 1;
- c |= block[6*i+j];
- }
- c += '.';
- if(c>'9') c += 7;
- if(c>'Z') c += 6;
- iobuf[i+2] = c;
- }
- iobuf[i+2] = 0;
- if(iobuf[1]==0)
- iobuf[1] = iobuf[0];
- return(iobuf);
- }