fdctref.c
资源名称:mpeg2编解码.zip [点击查看]
上传用户:hkgotone
上传日期:2013-02-17
资源大小:293k
文件大小:3k
源码类别:
Windows Mobile
开发平台:
C/C++
- /* fdctref.c, forward discrete cosine transform, double precision */
- /* Copyright (C) 1996, MPEG Software Simulation Group. All Rights Reserved. */
- /*
- * Disclaimer of Warranty
- *
- * These software programs are available to the user without any license fee or
- * royalty on an "as is" basis. The MPEG Software Simulation Group disclaims
- * any and all warranties, whether express, implied, or statuary, including any
- * implied warranties or merchantability or of fitness for a particular
- * purpose. In no event shall the copyright-holder be liable for any
- * incidental, punitive, or consequential damages of any kind whatsoever
- * arising from the use of these programs.
- *
- * This disclaimer of warranty extends to the user of these programs and user's
- * customers, employees, agents, transferees, successors, and assigns.
- *
- * The MPEG Software Simulation Group does not represent or warrant that the
- * programs furnished hereunder are free of infringement of any third-party
- * patents.
- *
- * Commercial implementations of MPEG-1 and MPEG-2 video, including shareware,
- * are subject to royalty fees to patent holders. Many of these patents are
- * general enough such that they are unavoidable regardless of implementation
- * design.
- *
- */
- #include <math.h>
- #include "config.h"
- #ifndef PI
- # ifdef M_PI
- # define PI M_PI
- # else
- # define PI 3.14159265358979323846
- # endif
- #endif
- /* global declarations */
- void init_fdct _ANSI_ARGS_((void));
- void fdct _ANSI_ARGS_((short *block));
- /* private data */
- static double c[8][8]; /* transform coefficients */
- void init_fdct()
- {
- int i, j;
- double s;
- for (i=0; i<8; i++)
- {
- s = (i==0) ? sqrt(0.125) : 0.5;
- for (j=0; j<8; j++)
- c[i][j] = s * cos((PI/8.0)*i*(j+0.5));
- }
- }
- void fdct(block)
- short *block;
- {
- int i, j, k;
- double s;
- double tmp[64];
- for (i=0; i<8; i++)
- for (j=0; j<8; j++)
- {
- s = 0.0;
- for (k=0; k<8; k++)
- s += c[j][k] * block[8*i+k];
- tmp[8*i+j] = s;
- }
- for (j=0; j<8; j++)
- for (i=0; i<8; i++)
- {
- s = 0.0;
- for (k=0; k<8; k++)
- s += c[i][k] * tmp[8*k+j];
- block[8*i+j] = (int)floor(s+0.499999);
- /*
- * reason for adding 0.499999 instead of 0.5:
- * s is quite often x.5 (at least for i and/or j = 0 or 4)
- * and setting the rounding threshold exactly to 0.5 leads to an
- * extremely high arithmetic implementation dependency of the result;
- * s being between x.5 and x.500001 (which is now incorrectly rounded
- * downwards instead of upwards) is assumed to occur less often
- * (if at all)
- */
- }
- }